Genotype | Phenotype (tail length) |
Number of individuals in population |
TLTL | long | 60 |
TLTS | medium | 40 |
TSTS | short | 100 |
In: Biology
Genotype | Phenotype (tail length) |
Number of individuals in population |
TLTL | long | 60 |
TLTS | medium | 40 |
TSTS | short | 100 |
The following is the information provided:
$$ \begin{array}{|l|l|} \hline \text { Genotype } & \begin{array}{l} \text { No. of } \\ \text { Individuals } \end{array} \\ \hline T^{\perp} T^{\mathcal{L}} & 60 \\ \hline T^{S} I^{S} & 100 \\ \hline T^{L} T^{5} & 40 \\ \hline \end{array} $$
Genotype frequency:
Long tail (homozygous long) \(=\frac{60}{200}=0.3(30 \%)\)
Short tail (homozygous short) \(=\frac{100}{200}=0.5(50 \%)\)
Medium tail (heterozygous) \(=\frac{40}{200}=0.2(20 \%)\)
Allele frequency:
Dominant allele \(=\frac{120+40}{400}=\frac{160}{400}=0.4\)
Recessive allele \(=\frac{200+40}{400}=\frac{240}{400}=0.6\)
From the genotype and allele frequencies, we can see that the following statements are true:
- Assuming random mating, each gamete has \(40 \%\) chance of having \(\mathrm{T}^{\mathrm{L}}\) allele and \(60 \%\) chance of having a \(\mathrm{T}^{5}\) allele
- In the entire cat population, \(60 \%\) of the alleles are \(\mathrm{T}^{\text {S }}\)
- In the entire cat population, the frequency of \(\mathrm{TL}\) allele is 0.4. Heterozygotes make up \(20 \%\) of the population
- Homozygotes make up \(80 \%\) of the population