In: Biology
Locus A has two alleles (A and a) while locus B has two alleles (B and b). The recombination frequency between locus A and locus B is 11%. A F1 heterozygote in trans configuration is mated with an aabb individual. What are the expected phenotypic percentages in the resulting progeny? Report your percentages to the tenths place and in the following format, replacing the "0.0" with your percentages.
Answer - Recombination frequency between locus A and locus B is 11%.
Trans configuration is mated with an aabb individual.
F1
A----------b a--------b
X
a----------B a--------b
Gametes
A--------b
a----------B A--------B a-------b X a------b
The recombination frequency is 11%. So A--------B and a-------b are recombinant.
Recombinant progeny = 11
Total progeny = 100
Therefore 11/100 = 0.11
Remaining are parent = 89. 89/2 = 44.5.
Parent A--------b = 44.5 = 44.5% or 0.445
Parent a----------B = 44.5 = 44.5% or 0.445
Recombinant offspring A--------B = 5.5% or 0.55
Recombinant offspring a-------b = 5.5% or 0.55