In: Statistics and Probability
A health researcher was interested in comparing three methods of weight loss: low-calorie diet, low-fat diet, and high-exercise regimen. He selected 15 moderately overnight subjects and randomly assigned 5 to each weight-loss program. The following weight reductions (in pounds) were observed after a one-month period: Low-fat diet: 7,6,8,8,6 low Calorie diet: 7,7,5,4,5 high exercise: 7,8,7,9,8
a) Test the null hypothesis that the extent of weight reduction does not differ by type of weight-loss program. (Set α=.01 level) (10 points) b) If the result at a) rejects the null hypothesis, use an appropriate multiple comparison procedure and determine where the significant differences occur. (5 points) c) Calculate the correlation ratio and interpret the result. (3 points)
Ho:extent of weight reduction does not differ by type of weight-loss program
Ha: extent of weight reduction differ by type of weight-loss program
A | B | C | ||||
count, ni = | 5 | 5 | 5 | |||
mean , x̅ i = | 7.000 | 5.60 | 7.80 | |||
std. dev., si = | 1.000 | 1.342 | 0.837 | |||
sample variances, si^2 = | 1.000 | 1.800 | 0.700 | |||
total sum | 35 | 28 | 39 | 102 | (grand sum) | |
grand mean , x̅̅ = | Σni*x̅i/Σni = | 6.80 | ||||
square of deviation of sample mean from grand mean,( x̅ - x̅̅)² | 0.040 | 1.440 | 1.000 | |||
TOTAL | ||||||
SS(between)= SSB = Σn( x̅ - x̅̅)² = | 0.200 | 7.200 | 5.000 | 12.4 | ||
SS(within ) = SSW = Σ(n-1)s² = | 4.000 | 7.200 | 2.800 | 14.0000 |
no. of treatment , k = 3
df between = k-1 = 2
N = Σn = 15
df within = N-k = 12
mean square between groups , MSB = SSB/k-1 =
6.2000
mean square within groups , MSW = SSW/N-k =
1.1667
F-stat = MSB/MSW = 5.3143
anova table | ||||||
SS | df | MS | F | p-value | F-critical | |
Between: | 12.40 | 2 | 6.20 | 5.31 | 0.0222 | 6.93 |
Within: | 14.00 | 12 | 1.17 | |||
Total: | 26.40 | 14 | ||||
α = | 0.01 | |||||
conclusion : | p-value>α , do not reject null hypothesis |
conclusion : | p-value>α , do not reject null hypothesis |
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