In: Biology
Both methionine and cysteine contain Sulphur atoms and may combine to form disulfide bridges? T/F
Both transcription and translation require primers for them to occur T/F
The conversion of acetyl CoA to malonyl CoA is the commitment step for β-oxidation. T/F
Ans:- False. Cysteine contains sulphur atoms and forms disulfide bridge because it contains the thiol group (S-H) which can easily form S-S (disulfide bidges) between two cysteine residue present in same polypeptide (intramolecular disulfide bond) or present in two different polypeptide chain (intermolecular disulfide bond). In contrast if you look at the structure of methionine you will find that sulphur is bonded by CH3 group, which is not a thiol group. Secondly, S-CH3 is very stable means sulphur in this state is not free to form disulfide bond. Thus, cysteine forms disulfide bridges whereas methionine cannot from inspite of presence of sulphur group because of lack of free sulphur group.
Ans:- False. Transcription and translation don't require pimer at all. Primers are the short stretch of nucleotides synthesized by an enzyme primase. Primers are required for DNA polymerase during DNA replication as DNA polymerase can add the nucleotide only when free 3' OH group is present. In case of transcription,when RNA polymerase copy the mRNA from DNA it does not need primer at all, because RNA polymerase can start transcription without the presence of 3' OH group. In case of translation, mRNA is translated into proteins where there is no use of primers and all.
Ans:- False. Conversion of acetyl CoA to malonyl CoA is not a commited step of beta oxidation. The conversion of acetyl CoA to malonyl CoA is the commited step during the fatty acid synthesis when acetyl CoA carboxylase add one carboxyl group to acetyl CoA. Beta oxidation is the breakdown of long chain of fatty acid to produce acetyl CoA that will channelize to kreb cycle for production of ATP.
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