In: Chemistry
1.Two hydrogen atoms can combine to form H2 but two He atoms cannot form He2 — Justify from MO viewpoint.
2.Ethyl benzene is treated with (i) Br2 and FeBr3 and (ii) Br2 and light or heat separately. Do you think the products will be same? Justify your answer.
3.The double bond in cyclohexene can be oxidized by potassium permanganate (KMNO4), whereas the double bonds in benzene do not undergo this oxidation reaction — Justify.
1. When two hydrogen atoms with 2 e- each combine to form H2, bond order = 1/2(2 - 0) = 1
So 1 bond exists between two H atoms to form H2 molecule
In case of He with 2 e-'s each, bond order = 1/2(2-2) = 0
So no bond exists between two He atoms and thus He2 is not formed.
2. When ethylbenzene is treated with,
(i) Br2 in FeBr3, an electrophilic aromatic bromination occurs on benzene ring to form para-bromotoluene product.
(ii) Br2 and light or heat separately, a free radical bromination occurs at the CH2 position of ethyl chain to give 1-bromoethylbenzene.
3. In benzene the double bonds are stabilized by aromaticity character which provides an extra stabilization to the system as opposed to If addition product is formed. The bond lengths are in between single and double bonds. Whereas, in cyclohexene isolated double bond has more pi-character and can be used in addition reaction to form more stable less strained ring structure.