In: Finance
1. A million-dollar oil drilling rig has a 6-year depreciable life and a $75,000 salvage value at the end of that time. Determine which one of the following methods provides the preferred depreciation schedule: DDB or SOYD. Show the depreciation schedule for the preferred method.
| SOYD is to be used as the DDB will never reach the salvage value and hence will result is capital gain at the end of the useful life. | ||||||||||||
| Year | Opening balance | Depreciation | Closing Balance | |||||||||
| 1 | 1000000 | 264285.7 | 735714.3 | |||||||||
| 2 | 735714.3 | 220238.1 | 515476.2 | |||||||||
| 3 | 515476.2 | 176190.5 | 339285.7 | |||||||||
| 4 | 339285.7 | 132142.9 | 207142.9 | |||||||||
| 5 | 207142.9 | 88095.24 | 119047.6 | |||||||||
| 6 | 119047.6 | 44047.62 | 75000 | |||||||||
| Year 1 depreciation = | ||||||||||||
| Depreciable amount | 1000000 - 75000 = | 925000 | ||||||||||
| Sum of years= | 1+2+3+4+5+6 = | 21 | ||||||||||
| 44047.62 | ||||||||||||
| Depreciation - | ||||||||||||
| Year | Year factor | Depreciation per factor | Depreciation for the year(Year factor x depreciation per factor) | |||||||||
| 1 | 6 | 44047.62 | 264285.7 | |||||||||
| 2 | 5 | 44047.62 | 220238.1 | |||||||||
| 3 | 4 | 44047.62 | 176190.5 | |||||||||
| 4 | 3 | 44047.62 | 132142.9 | |||||||||
| 5 | 2 | 44047.62 | 88095.24 | |||||||||
| 6 | 1 | 44047.62 | 44047.62 | |||||||||
| 925000 | ||||||||||||