In: Statistics and Probability
A basketball player has made 80% of his foul shots during the season. Assuming the shots are independent, find the probability that in tonight's game he does the following. a) Misses for the first time on his fourth attempt b) Makes his first basket on his fourth shot c) Makes his first basket on one of his first 3 shots
a)
Let the random variable X = number of trials until the first success occurs (such that number of successful attempt until first miss) and p is the probability of missing the foul shot (p = 1 - 0.80 = 0.20)
The random variable X follows geometric distribution with probability mass function,
Where, k is the number of trials.
Now, the probability of misses for the first time on his fourth attempt is,
b)
Let the random variable X = number of trials until the first success occurs (such that number of failed attempt until first success) and p is the probability of basket the foul shot (p = 0.80)
Now, the probability of makes his first basket on his fourth shot is,
c)
Let the random variable X = number of trials until the first success occurs (such that number of failed attempt until first success) and p is the probability of basket the foul shot (p = 0.80)
Now, the probability of makes his first basket on one of his first 3 shots