a.You have 40.0 mL of a 0.100 M solution of HClO, with a Ka of 3.0...

a.You have 40.0 mL of a 0.100 M solution of HClO, with a K_a of 3.0 x 10^-8. b. What is the pH of the solution after the addition of 30.0 mL of 0.200 M NaOH?

Expert Solution

millimoles of HClO = 40 x 0.1 = 4

millimoles of NaOH = 30 x 0.2 = 6

HClO + NaOH ----------------------> NaClO + H2O

4 6 0 0 --------------------> initial

0 2 4 4 ------------------> after reaction

strong base NaOH remained in the solution .

so [OH] = millimoles / total volume

= 2 / (40 +30)

= 0.0286 M

pOH = -log [OH-] = -log (0.0286)

pOH = 1.54

pH + pOH = 14

pH = 12.46

queen_honey_blossom answered 2 years ago

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