What is the pH of a 0.265 M HClO solution. The Ka of HClO is 2.9x10^-8.

Expert Solution

HClO ------------> H^+ (aq) + ClO^-

I 0.265 0 0

C -x +x +x

E 0.265-x +x +x

Ka = [H^+][ClO^-]/[HClO]

2.9*10^-8 = x*x/(0.265-x)

2.9*10^-8*(0.265-x) = x^2

x = 8.76*10^-5

{H+] = x = 8.76*10^-5 M

PH = -log[H+]

= -log8.76*10^-5

= 4.0574

queen_honey_blossom answered 3 years ago

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