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A 25.0 mL sample of 0.100 M barium chloride reacts with 40.0 mL of a 0.200...

A 25.0 mL sample of 0.100 M barium chloride reacts with 40.0 mL of a 0.200 M lead (II) sulfate solution to form barium sulfate and lead (II) chloride.

A) Write the balanced equation.

B) How many grams of lead (II) chloride will form?

C) If you make 0.560 grams of lead (II) chloride from this reaction in the lab, what is the percent yield?

D) How many grams of excess reagent are left over?

Solutions

Expert Solution

Limiting reagent- which reactants is consumed completely during the reaction and decides the amount of product.

queen_honey_blossom answered 1 year ago
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