Question

In: Chemistry

Part A It takes 55.0 J to raise the temperature of an 10.2 g piece of...

Part A

It takes 55.0 J to raise the temperature of an 10.2 g piece of unknown metal from 13.0∘C to 25.0 ∘C. What is the specific heat for the metal?

Part B

The molar heat capacity of silver is 25.35 J/mol⋅∘C. How much energy would it take to raise the temperature of 10.2 g of silver by 15.4 ∘C ?

I got 36.9 J for B and its correct

Part C

What is the specific heat of silver?

Solutions

Expert Solution

Part A:

The amount of heat required , Q = mcdt

Where

m = mass of the metal piece = 10.2 g

c = specific heat capacity of the metal = ?

dt = change in temperature = final - initial

    = 25.0 - 13.0 oC

    = 12.0 oC

Q = heat absorbed = 55.0 J

Plug the values we get c = Q / (mdt)

                                     = 55.0 / ( 10.2 x 12.0)

                                     = 0.449 J/(goC)

Part B :

We knowe that the molar mass of silver is = 107.9 g/mol

Given molar heat capacity of silver is 25.35 J/mol⋅∘C

So specific heat capacity of silver = molar heat capacity of silver/molar mass

                                                  = 25.35 J/mol⋅∘C / 107.9(g/mol)

                                                  = 0.235 J/(goC)

So amount of heat required , q = mcdt

Where

m = mass of silver = 10.2 g

c = specific heat capacity of silver = 0.235 J/(goC)

dt = raise in temperature = 15.4 oC

Plug the values we get q = 10.2x0.235x15.4

                                     = 36.9 J

Part C :

specific heat capacity of silver = molar heat capacity of silver/molar mass

                                                  = 25.35 J/mol⋅∘C / 107.9(g/mol)

                                                  = 0.235 J/(goC)


Related Solutions

Part A It takes 47.0 J to raise the temperature of an 9.50 g piece of...
Part A It takes 47.0 J to raise the temperature of an 9.50 g piece of unknown metal from 13.0∘C to 24.8 ∘C. What is the specific heat for the metal? Express your answer with the appropriate units. Cs= Parts B and C The next two questions pertain to silver. They have nothing to do with unknown metal described in Part A. Part B The molar heat capacity of silver is 25.35 J/mol⋅∘C. How much energy would it take to...
Compute the total quantity of heat (both in Kcal and J) required to raise the temperature...
Compute the total quantity of heat (both in Kcal and J) required to raise the temperature of 1.00 kg of ice at -10.0 degrees C to 1.00 kg of steam at 110.0 degrees C. Assume no loss of mass or heat in this process. Note that this will requires several computations that must be completely added up, and you must include all phase changes and use the correct specific heats.
A student heats a piece of 130 g of an unknown greyish metal to a temperature...
A student heats a piece of 130 g of an unknown greyish metal to a temperature of 99.2 celcius. she places the metal in a styrofoam cup that contains 55.7 g of water at a temperature of 23.0 celsius. the hot metal heats up the water in the cup to 31.4 celcius. calculate the specific heat of the metal?
4. In total, how much heat is required to raise the temperature of a 450 g...
4. In total, how much heat is required to raise the temperature of a 450 g sample of water (c = 4.18 J/oC.g) in a saucepan that has a heat capacity of 300 J/oC from 200C to 75oC a. If I burn 0.315 moles of hexane (C6H14) in a bomb calorimeter containing 5.65 liters of water, what’s the molar heat of combustion of hexane is the water temperature rises by 55.40 oC? The heat capacity of water is 4.18 J/g...
Calculate the quantity of energy, in joules, required to raise the temperature of 486 g tin...
Calculate the quantity of energy, in joules, required to raise the temperature of 486 g tin from room temperature, 25.0 °C, to its melting point, 231.9 °C, and then melt the tin at that temperature. (The specific heat capacity of tin is 0.227 , and the enthalpy of fusion of this metal is 59.2 J/g.)
Part B The amount of boiling water required to raise the temperature of 25.0 kgof water...
Part B The amount of boiling water required to raise the temperature of 25.0 kgof water in the bath to body temperature is 4.80 kg. In this process, the heat lost by the boiling water is equal to the heat gained by the room-temperature water. How much heat was transferred in this process? Express your answer to four significant figures and include the appropriate units. n this problem answers are requested to three significant digits for grading purposes. The true...
1.38 g H2 is allowed to react with 10.2 g N2 , producing 2.64 g NH3...
1.38 g H2 is allowed to react with 10.2 g N2 , producing 2.64 g NH3 .
1. A 5.88 kg piece of granite with a specific heat of 0.803 J g-1 °C-1...
1. A 5.88 kg piece of granite with a specific heat of 0.803 J g-1 °C-1 and a temperature of 85.1 °C is placed into 2.00 L of water at 19.0 °C. When the granite and water come to the same temperature, what will the temperature be? 2. The combustion of methane (the chief component of natural gas) follows the equation: CH4(g) + 2O2(g) → CO2(g) + 2H2O(g) ∆H° for this reaction is -802.3 kJ. How many grams of methane...
ONLY NEED SECOND PART A piece of music wire with a mass of 0.46 g is...
ONLY NEED SECOND PART A piece of music wire with a mass of 0.46 g is used in a piano for the key of F above middle C. The wire is to be tuned to a fundamental frequency of 349 Hz. Knowing that the wire is anchored between tightening posts that are 24 cm apart, determine the tension in the wire required to produce the correct note. (T=53.7 N) Find the temperature change needed in the room for the note...
The temperature of a 356 g piece of granite is increased from 32.3°C to 55.5°C. What...
The temperature of a 356 g piece of granite is increased from 32.3°C to 55.5°C. What is its change in entropy (J/K)? The specific heat capacity of granite is 0.790 J/g.K.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT