1.38 g H2 is allowed to react with 10.2 g N2 , producing 2.64 g NH3...

1.38 g H2 is allowed to react with 10.2 g N2 , producing 2.64 g NH3 .

Expert Solution

N2 + 3 H2 -----------------------> 2 NH3

28 g 6 g 34 g

10.2g 1.38 g ?

28 g N2 ---------------------> 6 g H2

10.2 g N2 ---------------------> 10 .2 x 6 / 28 = 2.19 g

actally we need 2.19 g of H2 but we have 1.38 g H2 . so

limiting reagent is H2

6 g H2 ----------------------> 34 g NH3

1.38 g H2 ------------------> 1.38 x 34 / 6 = 7.82 g

theoretical yield = 7.82 g

actal yield = 2.64 g

percent yield = ( 2.64 / 7.82 ) x 100

= 33.8 %

queen_honey_blossom answered 2 years ago

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