Question

In: Chemistry

1. A 5.88 kg piece of granite with a specific heat of 0.803 J g-1 °C-1...

1. A 5.88 kg piece of granite with a specific heat of 0.803 J g-1 °C-1 and a temperature of 85.1 °C is placed into 2.00 L of water at 19.0 °C. When the granite and water come to the same temperature, what will the temperature be?

2. The combustion of methane (the chief component of natural gas) follows the equation:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)


∆H° for this reaction is -802.3 kJ. How many grams of methane must be burned to provide enough heat to raise the temperature of 202.3 mL of water from 24.09 °C to 42.67 °C?

3. How much heat, in joules and in calories, must be removed from 1.58 mol of water to lower its temperature from 26.6 to 14.1°C? Include the sign in your answer.

4. A vat of 4.07 kg of water underwent a decrease in temperature from 61.38 to 58.44 °C. How much energy in kilojoules left the water? Include the sign in your answer. (For this range of temperature, use a value of 4.18 J·g-1·°C-1 for the specific heat of water.)

Solutions

Expert Solution

1.

Heat lost by Granite= Heat gained by water

Mass of granite* specific heat of granite* (85.1-T)= Mass of water* specific heat of water*(T- 19)

T= Equilibrium temperature reached by water and granite.

Assuming water density to be 1g/cc , 2 L of water correspond to 2000 gms

Mass of water= 2000gm, Specific heat of water= 4.18 j/g.deg.c

5.88*0.803*(85.1-T)= 2000* 4.18*(T-19)

4018.12-4.72T= 8360T-158840

4018.12+158840= 8364.72T

T=19.47 deg.c

2. delH= Enthalpy change of water = mass of water* specific heat of water* temperature differecne

Assuming density of water to 1g/ml, specific heat of water= 4.18 j/g.deg.c

Enthalpy change= 202.3*1*4.18*(42.67-24.09)=15711.51 joules= 15.712 Kj

Enthalpy change has to come from combustion of methane which is 802.3 KJ/mol of methane

Moles of methnane required= 15.712/802.3=0.019584

Mass of methane =molecular weight* moles= 0.019584*16=0.313 gms

3. Heat to be removed= moles of water* mass of water* specific heat of water* Temperature difference= 1.58*18*4.18*(26.6-14.1)=1486 joules

4. Heat left = 4.07*1000*4.18*(61.38-58.44)=50017.04 joules


Related Solutions

Specific heat of ice: 2.09 J/(g⋅∘C Specific heat of liquid water: 4.18 J/(g⋅∘C) Enthalpy of fusion:...
Specific heat of ice: 2.09 J/(g⋅∘C Specific heat of liquid water: 4.18 J/(g⋅∘C) Enthalpy of fusion: ΔHfus=334J Enthalpy of vaporization: ΔHvap=2250 J/g How much heat energy, in kilojoules, is required to convert 47.0 g of ice at −−18.0 ∘C∘C to water at 25.0 ∘C?
The value of specific heat for copper is 390 J/kg⋅C∘, for aluminun is 900 J/kg⋅C∘, and...
The value of specific heat for copper is 390 J/kg⋅C∘, for aluminun is 900 J/kg⋅C∘, and for water is 4186 J/kg⋅C∘. What will be the equilibrium temperature when a 225 g block of copper at 245 ∘C is placed in a 155 g aluminum calorimeter cup containing 835 g of water at 14.0 ∘C ? Express your answer using three significant figures.
The value of specific heat for copper is 390 J/kg⋅C∘, for aluminun is 900 J/kg⋅C∘, and...
The value of specific heat for copper is 390 J/kg⋅C∘, for aluminun is 900 J/kg⋅C∘, and for water is 4186 J/kg⋅C∘. Part A What will be the equilibrium temperature when a 275 g block of copper at 245 ∘C is placed in a 135 g aluminum calorimeter cup containing 855 g of water at 15.0 ∘C? Express your answer using three significant figures.' T=  ∘C
1. Specific heat of water is 4.184 J/g ˚C. What is the heat in KJ gained...
1. Specific heat of water is 4.184 J/g ˚C. What is the heat in KJ gained when 20 q of water is heated from 22˚C to 77˚C? 2. What is the heat in J to melt 100g of NaCl when the HF for NaCl is 518 J/g? 3. What is the heat in J to equate 50 g Acetic Acid when the HE = 390 J/g?
Given that the specific heat capacities of ice and steam are 2.06 J/g°C and 2.03 J/g°C,...
Given that the specific heat capacities of ice and steam are 2.06 J/g°C and 2.03 J/g°C, the molar heats of fusion and vaporization for water are 6.02 kJ/mol and 40.6 kJ/mol, respectively, and the specific heat capacity of water is 4.18 J/g°C, calculate the total quantity of heat evolved when 20.4 g of steam at 162°C is condensed, cooled, and frozen to ice at -50.°C.
Given that the specific heat capacities of ice and steam are 2.06 J/g°C and 2.03 J/g°C,...
Given that the specific heat capacities of ice and steam are 2.06 J/g°C and 2.03 J/g°C, the molar heats of fusion and vaporization for water are 6.02 kJ/mol and 40.6 kJ/mol, respectively, and the specific heat capacity of water is 4.18 J/g°C, calculate the total quantity of heat evolved when 13.2 g of steam at 192°C is condensed, cooled, and frozen to ice at -50.°C.
Given that the specific heat capacities of ice and steam are 2.06 J/g°C and 2.03 J/g°C,...
Given that the specific heat capacities of ice and steam are 2.06 J/g°C and 2.03 J/g°C, the molar heats of fusion and vaporization for water are 6.02 kJ/mol and 40.6 kJ/mol, respectively, and the specific heat capacity of water is 4.18 J/g°C, calculate the total quantity of heat evolved when 27.1 g of steam at 216°C is condensed, cooled, and frozen to ice at -50.°C. ______KJ Please show the steps
A 5.00 g sample of aluminum (specific heat capacity = 0.89 J °C-1 g-1) and a...
A 5.00 g sample of aluminum (specific heat capacity = 0.89 J °C-1 g-1) and a 10.00 g sample of iron (specific heat capacity = 0.45 J °C-1 g-1) are heated to 100.0 °C. The mixture of hot iron and aluminum is then dropped into 91.9 g of water at 23.7 °C. i) State the conditions for phase equilibrium of this system. NOTE: For an isolated system, the equilibrium state corresponds to the state with maximum entropy.
In an experiment, 300 g of aluminum (specific heat of 900 J/kg*K) at 120 Celsius is...
In an experiment, 300 g of aluminum (specific heat of 900 J/kg*K) at 120 Celsius is mixed with 60 g of water at 20 Celsius, with the mixture thermally isolated. You will need to look up the specific heat of water. (a) What is the equilibrium temperature? (b) What is the entropy change for the aluminum block? (c) What is the entropy change for the water? (d) What is the entropy change for the aluminum-water system?
A 100 g piece of granite and a 100 g piece of lead are placed in...
A 100 g piece of granite and a 100 g piece of lead are placed in an oven that is at 100°C. The initial temperature of the pieces are 25°C. After a couple of minutes, neither one is at 100°C, but which one is warmer? Which one will reach 100°C first? How much energy will it take for both of the objects to reach 100°C?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT