Question
In: Statistics and Probability
the standard deviation of the diameter of 28 oranges was 0.34 inch. find the 99% confidence...
the standard deviation of the diameter of 28 oranges was 0.34 inch. find the 99% confidence interval of the true standard deviation of the diameter of the orages.
Solutions
Expert Solution
Solution :
Given that,
s = 0.34
s2 = 0.1156
2L
=
2
/2,df = 49.645
2R
=
21 - /2,df = 11.808
The 99% confidence interval for 
is,
(n
- 1)s2 /
2/2 <
<
(n - 1)s2 /
21 - /2
27
* 0.1156 / 49.645 <
<
27 * 0.1156 / 11.808
0.25 <
< 0.51
(0.25 , 0.51)
orchestra answered 2 years agoRelated Solutions
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10
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35
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S=
n=
〖χ²〗_R=(chi-square right tail)=
〖χ²〗_L=(chi-square left tail)=
80% confidence interval:
Interpretation:
〖χ²〗_R= 〖χ²〗_L= 90% confidence interval:
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〖χ²〗_R= 〖χ²〗_L= 99% confidence interval:
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