Question

In: Statistics and Probability

Calculate true standard deviation of the diameter of a large batch of tires to a confidence...

Calculate true standard deviation of the diameter of a large batch of tires to a confidence level of 99% if the measured standard deviation in the diameter for a sample of 30 tires is 0.0795 cm.

Solutions

Expert Solution

Solution :  

Given that,

c = 99% = 0.99

s = 0.0795

n = 30

d.f. = n - 1 = 30 - 1 = 29

= 1 - 0.99 = 0.01

/ 2 = 0.005

1 - ( / 2) = 0.995

Now , using chi square table ,

= 0.025,29 = 52.335

=  0.975,26 = 13.121

The 99% confidence interval for is,

0.0795  [(30 - 1 ) / 52.335] < <  0.0795[(30 - 1 ) / 13.121]

0.059 < < 0.118

The 99% confidence interval for is ( 0.059 , 0.118 )


Related Solutions

the standard deviation of the diameter of 28 oranges was 0.34 inch. find the 99% confidence...
the standard deviation of the diameter of 28 oranges was 0.34 inch. find the 99% confidence interval of the true standard deviation of the diameter of the orages.
Calculate 80%, 90% and 99% confidence intervals for the standard deviation. Include here the sample standard...
Calculate 80%, 90% and 99% confidence intervals for the standard deviation. Include here the sample standard deviation and sample size -30pts- S= n= 〖χ²〗_R=(chi-square right tail)= 〖χ²〗_L=(chi-square left tail)= 80% confidence interval: Interpretation: 〖χ²〗_R= 〖χ²〗_L= 90% confidence interval: Interpretation: 〖χ²〗_R= 〖χ²〗_L= 99% confidence interval: Interpretation: How do these confidence intervals relate to the population standard deviation you calculated in question #1, when the set of data was treated as a population? -5 pts- Use the sample you chose to perform...
Use the indicated margin of error, the confidence level, and the population standard deviation to calculate...
Use the indicated margin of error, the confidence level, and the population standard deviation to calculate the minimum sample size required to estimate an unknown population mean. a) Error margin: 0.5 inch, confidence level: 95%, Standard deviation: 2.5 inch. b) margin of error: 0.25 seconds, confidence level: 99%, standard deviation: 5.4 seconds. c) Margin of error: $ 1, confidence level: 99%, standard deviation: $ 12. d) Margin of error: 1.5 mm, confidence level: 95%, standard deviation: 8.7 mm
one can calculate the 95% confidence interval for the mean with the population standard deviation knowing...
one can calculate the 95% confidence interval for the mean with the population standard deviation knowing this gives us an upper and lower confidence limit what happens if we decide to calculate the 99% confidence interval describe how the increase in the confidence level has changed the width of the confidence interval
One can calculate the 95% confidence interval for the mean with the population standard deviation known....
One can calculate the 95% confidence interval for the mean with the population standard deviation known. This will give us an upper and a lower confidence limit. What happens if we decide to calculate the 99% confidence interval? Describe how the increase in the confidence level has changed the width of the confidence interval. Do the same for the confidence interval set at 80%. Include an example with actual numerical values for the intervals in your post to help with...
One can calculate the 95% confidence interval for the mean with the population standard deviation known....
One can calculate the 95% confidence interval for the mean with the population standard deviation known. This will give us an upper and a lower confidence limit. What happens if we decide to calculate the 99% confidence interval? Your task for this discussion is as follows: Describe how the increase in the confidence level has changed the width of the confidence interval. Do the same for the confidence interval set at 80%. Include an example with actual numerical values for...
Consider a large population which has true mean µ and true standard deviation σ. We take...
Consider a large population which has true mean µ and true standard deviation σ. We take a sample of size 3 from this population, thinking of the sample as the RVs X1, X2, X3 where Xi can be considered iid (independent identically distributed). We are interested in estimating µ. (a) Consider the estimator ˆµ1 = X1 + X2 − X3. Is this estimator biased? Show your work (b) Find the variance of ˆµ1. (c) Consider the estimator ˆµ2 = X1+X2+X3...
Calculate 80%, 90% and 99% confidence intervals for the player weight standard deviation. Include here the...
Calculate 80%, 90% and 99% confidence intervals for the player weight standard deviation. Include here the sample standard deviation and sample size -30pts- S= 16.47 n= 50 〖 χ²〗_R=(chi-square right tail)= 〖χ²〗_L=(chi-square left tail)= 80% confidence interval and interpretation: 〖χ²〗_R= 〖χ²〗_L= 90% confidence interval and interpretation: 〖χ²〗_R= 〖χ²〗_L= 99% confidence interval and interpretation: How do these confidence intervals relate to the population standard deviation?
Given a normal distribution of scores calculate 95% confidence interval for the standard deviation? Given: Sample...
Given a normal distribution of scores calculate 95% confidence interval for the standard deviation? Given: Sample mean = 87.1667. Sample size is 12. Sample variance = 60.88.
Calculate the two-sided 95% confidence interval for the population standard deviation (sigma) given that a sample...
Calculate the two-sided 95% confidence interval for the population standard deviation (sigma) given that a sample of size n=8 yields a sample standard deviation of 7.96.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT