Question

In: Biology

Black body (b) and purple eye (pr) are recessive autosomal mutations in Drosophila. Bridges crossed b/b...

Black body (b) and purple eye (pr) are recessive autosomal mutations in Drosophila. Bridges crossed b/b females and pr/pr males. F2 cross produced 684 wild-type, 371 black-bodied, and 300 purple-eyes flies. Do these result indicate that the b and pr genes are closely linked? Explain. Remember that there is no crossing over in male Drosophila

Solutions

Expert Solution

b - allele for black body - recessive

pr - allele for purple eye - recessive

B - wild type for body colour

Pr - wild type for eye colour.

BB PrPr, Bb PrPr, Bb Prpr and BB Prpr are the wild types.

Bridges crossed b/b females and pr/pr males

In this cross, since nothing is said about eye colour genotype of female and body colour genotype of male, let's consider them as homozygous dominant for those respective traits.

Cross By Bridges:

PrPr bb (female) X prpr BB (male)

'X' represents cross or mating

This cross produces only one type of progeny in the F1 i.e., Prpr Bb

To produce F2, we need to cross amoung the F1 individuals.

Thr cross: (Considering the genes are not linked)

Prpr Bb (female) X Prpr Bb (male)

Each of the parents will produce 4 types of gametes viz. Pr B, Pr b, pr B and pr b

This is a typical dihybrid situation, which produces the typical ratio of 9:3:3:1.

That is :

9 wild : 9Black : 9 Purple : 1 black and purple

But, the data givem has a very huge departure from this ratio. Hence the genes are linked, i.e. are found on the same chromosome.

To find if both the genes are tightly linked, we have to find out the phenotypic ratio when genes are tightly linked, i.e. 0% recombination for both the parents. A scheme to find out that ratio is attached with this answer. Please refer that.

The ratio of Wild : Black : Purple if genes are tightly linked was found to be 2 : 1 : 1.

As per the data given, there are 684 wild, 371 black bodied and 300 purple eyed flies.

The phenotype is in the ratio of 2.28 : 1.23 : 1 (Wild : Black : Purple).

This is approximately equal to 2:1:1.

Hence, we can conclude that there is tight linkage between the two genes.


Related Solutions

In Drosophila melanogaster, black body (b) is recessive to gray body (b+), purple eyes (pr) are...
In Drosophila melanogaster, black body (b) is recessive to gray body (b+), purple eyes (pr) are recessive to red eyes (pr+), and vestigial wings (vg) are recessive to normal wings (vg+). These three genes are linked with pr located between b and vg at a genetic distance of 6 cM from b and 13 cM from vg. Previous experiments have shown that the interference associated with these three genes is 0.5. A fly with a black body, purple eyes and...
Drosophila females heterozygous for three recessive mutations, a, b, and c were crossed to males homozygous...
Drosophila females heterozygous for three recessive mutations, a, b, and c were crossed to males homozygous for all three mutations. The cross yielded the following results. Phenotype Number A B C - 75 A B c - 348 A b c - 96 a B C - 110 a b C - 306 a b c - 65 Determine the gene order. Determine the distance between genes . Make a genetic map of the genes.
A Drosophila female homozygous mutant for two recessive genes (a and b) is crossed to a...
A Drosophila female homozygous mutant for two recessive genes (a and b) is crossed to a wild-type male. The F1 are all wild-type. An F1 female is crossed to a double-mutant male and the following phenotypes were seen in the F2: a b 497 + + 460 a + 465 + b 426 Total 1848 Perform a “best fit” or apriori χ2 analysis to determine if genes a and b assort independently. Give the value for χ2, DF and Probability;...
In tomatoes, a heterozygous plant with normal fruit and purple stems is crossed with a recessive...
In tomatoes, a heterozygous plant with normal fruit and purple stems is crossed with a recessive plant having fasciated fruit and green stems. The following distribution of offspring is observed: normal fruit, purple stems 38.5%  fasciated fruit, green stems 38.5% normal fruit, green stems 11.5%   fasciated fruit, purple stems 11.5% What conclusion can be made regarding the loci for fruit shape and stem color? HINT determine the RF What the loci and RF here mean? How to answer this question?
In Drosophila black body (B) is dominant to gray (b) and long wings (L) is dominant...
In Drosophila black body (B) is dominant to gray (b) and long wings (L) is dominant to short wings (l). The F1 flies were produced by crossing a homozygous black, homozygous long winged fly with a gray short winged fly. (4) a) Give the genotypes of the Parents and the F1. b) If an F1 is testcrossed, what is the expected phenotypic ratio? c) If the F1 are allowed to interbreed what are the expected phenotypes and probably proportions in...
Drosophila has three linked autosomal genes that determine different traits. These genes are black (b), vestigial...
Drosophila has three linked autosomal genes that determine different traits. These genes are black (b), vestigial (vg), and singed(sn). Each of the three genes has two alleles: a dominant wild type allele, indicated by a "+" (plus) and a recessive mutant allele indicated by a "-" (minus). (These mutant alleles cause dark black spots, short "vestigial" wings, and bent "singed" hairs, respectively, when homozygous). A testcross is conducted between females that all have the same genotype and are triple heterozygotes...
Bar eye (B) is a dominant and sex-linked trait of Drosophila. Curved wings (cu) and black...
Bar eye (B) is a dominant and sex-linked trait of Drosophila. Curved wings (cu) and black body (bl) are recessive traits, both found on chromosome 2, separated by 24 map units. A homozygous Bar-eyed, black-bodied female is crossed to a true-breeding male expressing curved wings. The heterozygous F1 female is then crossed to a male expressing all three traits. At what frequency among the F2 would you expect to find a completely wild type male? How often would you find...
Scalloped (sd) wing is an X-linked recessive and ebony (e) body color is an autosomal recessive...
Scalloped (sd) wing is an X-linked recessive and ebony (e) body color is an autosomal recessive mutation in Drosophila. What proportion of scalloped, ebony colored females is expected in the F2 starting with a true breeding scalloped female which is wild type for ebony mating with a true breeding male mutant only for ebony. a. 1/16 b. 3/16 c. 0 d. 1/8 e. 1/32
Familial Mediterranean Fever (FMF) is an autosomal recessive genetic condition due to mutations in the MEFV...
Familial Mediterranean Fever (FMF) is an autosomal recessive genetic condition due to mutations in the MEFV gene that encodes pyrin, a protein that functions in the immune inflammatory response. The following numbers are from a representative sample of individuals from Greece with their respective genotypes. (note- capital letters indicate the wildtype allele and lower-case letters represent mutant allele) 216   MEFV/MEVF                  82 MEVF/mevf                       4 mevf/mevf In France, the incidence of Familial Mediterranean Fever is 0.80% or 0.008. Use this to answer...
The allele b gives Drosophila flies a black body, and b+ gives brown, the wild-type phenotype....
The allele b gives Drosophila flies a black body, and b+ gives brown, the wild-type phenotype. The allele wx of a separate gene gives waxy wings, and wx+ gives nonwaxy, the wild-type phenotype. The allele cn of a third gene gives cinnabar eyes, and cn+ gives red, the wild-type phenotype. A female heterozygous for these three genes is testcrossed, and 2,424 progeny (you could also use n=2,423) are classified as follows: cn+ · wx+ · b 101 cn · wx+...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT