Question

In the figure, a 0.24 kg block of cheese lies on the floor of a 920 kg elevator cab that is being pulled upward by a cable through distance d1 = 2.1 m and then through distance d2 = 10.6 m. (a) Through d1, if the normal force on the block from the floor has constant magnitude FN = 2.97 N, how much work is done on the cab by the force from the cable? (b) Through d2, if the work done on the cab by the (constant) force from the cable is 91.92 kJ, what is the magnitude of FN?

Answer 1

The concept used is of force balance and connected mass system , acceleration of cheese block and the elevator is same because cheese block and elevator system behave as the connected mass . Initially i draw the free body diagram of cheese alone and cheese plus elevator system , after that balances all the forces and get the desired result asked in the question

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