A block of mass 220 kg initially at rest is pushed along the floor by a...

A block of mass 220 kg initially at rest is pushed along the floor by a force F directed at an angle 40o below the positive x-axis. The force pushes against a friction force with coefficient µ = 0.25. Calculate the magnitude of the force F, that will give the block an acceleration of 3.6 m/s2

Solutions

Expert Solution

Gravitational acceleration = g = 9.81 m/s²

Mass of the block = m = 220 kg

Force applied on the block = F

Angle at which the force is applied = = 40^o

Normal force on the block from the floor = N

Coefficient of friction = = 0.25

Friction force on the block = f

Acceleration of the block = a = 3.6 m/s²

From the free body diagram,

In the vertical direction,

In the horizontal direction,

F = 2.2 x 10³ N

Magnitude of the force that will give the block an acceleration of 3.6 m/s² = 2.2 x 10³ N

genius_generous answered 1 year ago

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