Block A in the figure below has mass 1.30 kg , and block B has mass...

Block A in the figure below has mass 1.30 kg , and block B has mass 2.85 kg . The blocks are forced together, compressing a spring S between them; then the system is released from rest on a level, frictionless surface. The spring, which has negligible mass, is not fastened to either block and drops to the surface after it has expanded. Block B acquires a speed of 1.20 m/s .

Part A

What is the final speed of block A?

Part B

How much potential energy was stored in the compressed spring?

Expert Solution

part A)

by linear momentum conservation

m1v1 =m2v2

1.3 v1 =2.85*1.2

v1 =2.63 m/s......speed of block A

Part B)

potential energy was stored in the compressed spring =1/2 m1v1² +1/2 m2v2²

=0.5*1.3*(2.63)² +0.5*2.85*(1.2)²

=6.5J

genius_generous answered 2 years ago

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