Question

In a study on the relationship of sleeping habits and performance in clinical work, 100 student nurses were cross-classified according to clinical performance and sleeping habits. The investigator wished to determine if there is an association between clinical performance and sleeping habits of student nurses at the 0.01 level of significance. The data and (expected values) are given below.

	Sleeping Habits
Clinical Performance	Poor	Good	Total
Poor	20 ( 12 )	10 ( 18 )	30
Satisfactory	20 ( 28 )	50 ( 42 )	70
Total	40	60	100

State the full conclusion for this test when the null hypothesis is rejected.

Answer 1

null hypothesis:Ho: : there is not an association between clinical performance and sleeping habits of student nurses

Alternate hypothesis:Ho: : there is an association between clinical performance and sleeping habits of student nurses

degree of freedom(df) =(rows-1)*(columns-1)=		1
for 1 df and 0.01 level , critical value       χ2=		6.635
Decision rule : reject Ho if value of test statistic X2>6.635

Applying chi square test of independence:

Expected	Ei=row total*column total/grand total	Poor	Good	Total
	Poor	12.0000	18.0000	30
	Satisfactory	28.0000	42.0000	70
	total	40	60	100
chi square    χ2	=(Oi-Ei)2/Ei	Poor	Good	Total
	Poor	5.3333	3.5556	8.8889
	Satisfactory	2.2857	1.5238	3.8095
	total	7.6190	5.0794	12.6984
test statistic X2 =		12.698

since test statistic falls in rejection region we reject null hypothesis

we have sufficient evidence to conclude that there is an association between clinical performance and sleeping habits of

student nurses.