To prepare 0.250 L of 0.100 M aqueous NaCl (58.4 g/mol), one may

Expert Solution

WE KNOW THAT

Molarity = Number of mole of solute/Volume of solution.

M= Number of mole of NaCl / Volume of solution.

0.100 = Number of mole of NaCl /0.250L.

Than

Number of mole of NaCl = 0.100*0.250

= 0.0250.

SO Mass of NaCl = mole* molecular weight

0.0250*58.4 =1.46g

queen_honey_blossom answered 2 years ago

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