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3)Suppose a solution is prepared by dissolving 15.0 g NaOH in 0.150 L of 0.250 M...

3)Suppose a solution is prepared by dissolving 15.0 g NaOH in 0.150 L of 0.250 M nitric acid. What is the final concentration of OH- ions in the solution after the reaction has gone to completion. Assume that there is no volume change when adding the grams of NaOH.

Solutions

Expert Solution

mass of NaOH = 15 g

molar mass of NaOH = 40 g/mol

moles of NaOH = 15 / 40

                          = 0.375

moles of HNO3 = molarity x volume

                          = 0.250 x 0.150

                           = 0.0375

so

0.0375 moles of HNO3 react with 0.0375 moles of NaOH

remaining moles of NaOH = 0.375 - 0.0375 = 0.3375

final conentration of OH- = 0.3375 / volume

                                          = 0.3375 / 0.150

                                           =   2.25 M

queen_honey_blossom answered 4 months ago
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