What volume of 0.20 M NaCl(aq) contains 10.0 g of NaCI (molar mass 58 g/mol)?

What volume of $0.20 M \mathrm{NaCl}(a q)$ contains $10.0 \mathrm{~g}$ of $\mathrm{NaCl}$ (molar mass $58 \mathrm{~g} / \mathrm{mol}$ )?

Expert Solution

Molarity $=\frac{\omega}{m \times V}$

W $\Rightarrow$ mass of soluteren

$m=$ molar mass solute

V = Volume of solution $(L)$

Molarity $=0.20 M / \mathrm{L}$

$w=10 \cdot 0 \mathrm{~g}$

$m=58 g/mol$

v $=\frac{10.0}{58 \times 0.2} = 0.862L$

Dr. OWL answered 4 years ago

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