In: Physics
Given the two charged particles shown in the figure below, find the electric field at the origin. (Let q1 = −26.00 nC and q2 = 7.00 nC. Express your answer in vector form.) q1 is at (2,4) and q2 is at (-2,3)
The position vectors of origin w.r.t each particle can be given as
r1 = -2 - 4
r2 = 2 - 3
Now electric field by a charged particle is given as E = kq/r3 , k = 1/4 = 9 x 109
Which means that
E1 = kq1r1/|r1|3 = 9 x 109 x (-26 nC) x (-2 - 4)/(22 + 42)3/2 = 5.2324 + 10.4648 N/C
E1 = kq1r1/|r1|3 = 9 x 109 x (7 nC) x (2 - 3)/(22 + 32)3/2 = 1.344(2 - 3) = 2.688 - 4.032 N/C
Net electric field on origin can be given as E = E1 + E2 = 7.92 + 6.4328