In: Physics
Given the two charged particles shown in the figure below, find the electric field at the origin. (Let q1 = −26.00 nC and q2 = 7.00 nC. Express your answer in vector form.) q1 is at (2,4) and q2 is at (-2,3)
The position vectors of origin w.r.t each particle can be given as
r1 = -2
- 4
r2 = 2
- 3
Now electric field by a charged particle is given as E =
kq/r3 ,
k = 1/4
= 9 x 109
Which means that
E1 =
kq1r1/|r1|3
= 9 x 109 x (-26 nC) x (-2
- 4
)/(22
+ 42)3/2 = 5.2324
+ 10.4648
N/C
E1 =
kq1r1/|r1|3
= 9 x 109 x (7 nC) x (2
- 3
)/(22
+ 32)3/2 = 1.344(2
- 3
)
= 2.688
- 4.032
N/C
Net electric field on origin can be given as E = E1 +
E2 = 7.92
+ 6.4328