In: Physics
M, a solid cylinder (M=1.83 kg, R=0.117 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.690 kg mass, i.e., F = 6.769 N. Calculate the angular acceleration of the cylinder. Because the bearing is thin, the moment of inertia of the bearing is essentially that of a solid cylinder
If instead of the force F an actual mass m = 0.690 kg is hung from the string, find the angular acceleration of the cylinder.
How far does m travel downward between 0.490 s and 0.690 s after the motion begins?
The cylinder is changed to one with the same mass and radius, but a different moment of inertia. Starting from rest, the mass now moves a distance 0.496 m in a time of 0.550 s. Find Icm of the new cylinder.