a.) M, a solid cylinder (M=2.11 kg, R=0.137 m) pivots on a thin, fixed, frictionless bearing....

a.) M, a solid cylinder (M=2.11 kg, R=0.137 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.610 kg mass, i.e., F = 5.984 N. Calculate the angular acceleration of the cylinder. a.)

b.) If instead of the force F an actual mass m = 0.610 kg is hung from the string, find the angular acceleration of the cylinder.

c.) How far does m travel downward between 0.590 s and 0.790 s after the motion begins?

d.) The cylinder is changed to one with the same mass and radius, but a different moment of inertia. Starting from rest, the mass now moves a distance 0.328 m in a time of 0.490 s. Find I_cm of the new cylinder.

Expert Solution

genius_generous answered 7 months ago

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