A 2.50-kg grinding wheel is in the form of a solid cylinder of radius 0.100 m....

A 2.50-kg grinding wheel is in the form of a solid cylinder of radius 0.100 m.

1- What constant torque will bring it from rest to an angular speed of 1200 rev/min in 2.5 s?

2- Through what angle has it turned during that time?

3- Use equation W=τz(θ2−θ1)=τzΔθ to calculate the work done by the torque.

4- What is the grinding wheel’s kinetic energy when it is rotating at 1200 rev/min?

5- Compare your answer in part (D) to the result in part (C).

Expert Solution

genius_generous answered 6 months ago

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