How many moles of NaH2PO4 and how many moles of H3PO4 are needed to make one...

How many moles of NaH2PO4 and how many moles of H3PO4 are needed to make one liter of a 450. mM phosphate buffer with a pH of 2.6? The pKa's for phosphoric acid are 2.16, 7.21, and 12.32.

ph= pka + log (conj base/conj acid )

Expert Solution

total no of mol of phosphatebuffer = M*V = 450*1 = 450 mmol

pH of phosphate buffer = pka1 + log[NaH2PO4/H3PO4]

pka1 of H3PO4 =2.16

[NaH2PO4] = x

[H3PO4] = 450-x

2.6 = 2.16 + log(x/(450-x))

x = 330.135

[NaH2PO4] = x = 330.135 mmol

= 0.33 mol

[H3PO4] = 450-x = 450-330.135 = 119.86 mmol

= 0.11986 mol

queen_honey_blossom answered 2 years ago

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