In: Chemistry
How many moles of OH- ions are present in 422mL of a 1.21 molar solution of Ba(OH)2?
no of moles of Ba(OH)2 = molarity * volume in L
= 1.21*0.422
= 0.51 moles
Ba(OH)2 ------------------> Ba^2+ (aq) + 2OH^-
0.51 moles 2*0.51moles
no of moles of OH^- = 2*0.51 = 1.02 moles