In: Math
Question 1. Let V and W be finite dimensional vector spaces over a field F with dimF(V ) = dimF(W) and let T : V → W be a linear map. Prove there exists an ordered basis A for V and an ordered basis B for W such that [T] A B is a diagonal matrix where every entry along the diagonal is either a 0 or a 1.
Hint 1. Suppose A = {~v1, . . . , ~vn} and B = { ~w1, . . . , ~wn}. If the k th column of [T] A B consists of all zeros, what can you deduce?
Hint 2. Suppose A = {~v1, . . . , ~vn} and B = { ~w1, . . . , ~wn}. If the k th column of [T] A B has a one in the k th entry and all other entries are zero, what can you deduce?
Hint 3. Now construct bases with the properties found in Hint 1 and Hint 2.
Hint 4. Theorem 18 part 5 is your friend.
Hint 5. The proof of the Rank-Nullity Theorem is your best friend.
here V and W be finite dimensional vector space and dim V= dim W
let the dimension=n imply in the basis we should have n elements
hence A={v1,v2,....,vn} and B={w1,w2,.....,wn} be the basis of V and W respectively
then T(v1)=w1=1.w1+0.w2+.....+0.wn
T(v2)=w2=0.w1+1.w2+.......+0.wn
:
similarly T(vn)=wn=0.w1+0.w2+......+1.wn
so by these basis properties we get the matrix
C= which is a diagonal matrix with entries 0 and 1