Question

In: Chemistry

8.00g of NaOH are dissolved in water to make 3.00L of solution. What is the concentration...

8.00g of NaOH are dissolved in water to make 3.00L of solution. What is the concentration of hydronium ions, [H3O+], in this solution?

Expert Solution

Solution

Given data

mass of NaOH = 8.00 g

volume = 3.00 L

[H3O+] = ?

lets first calculate moles of NaOH

formula to calculate moles is as follows

moles = mass in gram / molar mass

moles of NaOH = 8.00 g / 39.997 g per mol

= 0.200 mol NaOH

now lets calculate molarity of NaOH

molarity = moles / volume in liter

molarity of NaOH = 0.200 mol / 3.00 L

= 0.06667 M

since NaOH and OH- has 1 : ratio therefore concnetration of OH- is same as concnetration of NaOH

therefore [OH-] = 0.06667 M

now lets calculate concentration of H3O+

Kw = [H3O+] [OH-]

Kw = 1*10^-14

Lets put the values in the formula and solve for [H3O+]

1*10^-14 = [ H3O+] [ 0.06667]

1*10^-14/ 0.06667 = [H3O+]

1.49*10^-13 M = [H3O+]

Therefore concentration of hydronium ion [H3O+] = 1.49*10^-13 M

queen_honey_blossom answered 2 years ago

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