In: Chemistry
A 29.0-g sample of NaOH is dissolved in water, and the solution is diluted to give a final volume of 1.60 L. The molarity of the final solution isA) 18.1 M B) 0.453 M C) 0.725 M D) 0.0552 M E) 0.862 M
Given mass of NaOH , m = 29.0 g
MOlar mass of NaOH is = At.mass of Na + At.mass of O + At.mass of H
= 23 + 16 + 1
= 40 g/mol
So the number of moles of NaOH , n = mass/molarmass
= 29.0 g / 40 (g/mol)
= 0.725 mol
Volume of the solution , V = 1.60 L
Molarity of the solution , M = number of moles / volume in L
= 0.725 mol / 1.60 L
= 0.453 mol / L
= 0.453 M
So Molaity of the solution is 0.453 M
Therefore option (B) is correct.