In: Statistics and Probability
In this problem, assume that the distribution of differences is
approximately normal. Note: For degrees of freedom
d.f. not in the Student's t table, use
the closest d.f. that is smaller. In
some situations, this choice of d.f. may increase
the P-value by a small amount and therefore produce a
slightly more "conservative" answer.
Do professional golfers play better in their last round? Let row
B represent the score in the fourth (and final) round, and
let row A represent the score in the first round of a
professional golf tournament. A random sample of finalists in the
British Open gave the following data for their first and last
rounds in the tournament.
B: Last | 72 | 66 | 74 | 71 | 71 | 72 | 68 | 68 | 74 |
A: First | 67 | 69 | 63 | 71 | 65 | 71 | 71 | 71 | 71 |
Do the data indicate that the population mean score on the last round is higher than that on the first? Use a 5% level of significance. (Let d = B − A.)
(a) What is the level of significance?
State the null and alternate hypotheses. Will you use a
left-tailed, right-tailed, or two-tailed test?
H0: μd > 0; H1: μd = 0; right-tailedH0: μd = 0; H1: μd < 0; left-tailed H0: μd = 0; H1: μd ≠ 0; two-tailedH0: μd = 0; H1: μd > 0; right-tailed
(b) What sampling distribution will you use? What assumptions are
you making?
The standard normal. We assume that d has an approximately normal distribution.The Student's t. We assume that d has an approximately normal distribution. The Student's t. We assume that d has an approximately uniform distribution.The standard normal. We assume that d has an approximately uniform distribution.
What is the value of the sample test statistic? (Round your answer
to three decimal places.)
(c) Find (or estimate) the P-value.
P-value > 0.250
0.125 < P-value < 0.250
0.050 < P-value < 0.125
0.025 < P-value < 0.050
0.005 < P-value < 0.025
P-value < 0.005
Sketch the sampling distribution and show the area corresponding to
the P-value.
At the α = 0.05 level, we fail to reject the null
hypothesis and conclude the data are statistically significant.At
the α = 0.05 level, we reject the null hypothesis and
conclude the data are not statistically
significant. At the α = 0.05 level,
we fail to reject the null hypothesis and conclude the data are not
statistically significant.At the α = 0.05 level, we reject
the null hypothesis and conclude the data are statistically
significant.
(d) Based on your answers in parts (a) to (c), will you reject or
fail to reject the null hypothesis? Are the data statistically
significant at level α?
(e) State your conclusion in the context of the application.
Fail to reject the null hypothesis, there is sufficient evidence to claim that the population score on the last round is higher than that on the first.Reject the null hypothesis, there is sufficient evidence to claim that the population score on the last round is higher than that on the first. Reject the null hypothesis, there is insufficient evidence to claim that the population score on the last round is higher than that on the first.Fail to reject the null hypothesis, there is insufficient evidence to claim that the population score on the last round is higher than that on the first.
We are given the following data and are asked to tets the hypothesis that population mean score is higher in the last round than that on the first round.
B:Last | 72 | 66 | 74 | 71 | 71 | 72 | 68 | 68 | 74 |
---|---|---|---|---|---|---|---|---|---|
A:First | 67 | 69 | 63 | 71 | 65 | 71 | 71 | 71 | 71 |
a) The level of significance is 5% or 0.05.
Null hypothesis
i.e., population mean score is same for the last round and for the first round.
Alternate hypothesis
(right tailed)
i.e., population mean score for last round is higher than that on the first round.
b) We use the Student's t and assume that d has an approximately normal distribution since the sample size is small.
To find the the test statistic we find the mean and standard deviation for the last round and the first round.
Let the score of the last round be represented as x and and the score of the first round be represented as y.
xi | yi | di=xi-yi | di2 |
---|---|---|---|
72 | 67 | 5 | 25 |
66 | 69 | -3 | 9 |
74 | 63 | 11 | 121 |
71 | 71 | 0 | 0 |
71 | 65 | 6 | 36 |
72 | 71 | 1 | 1 |
68 | 71 | -3 | 9 |
68 | 71 | -3 | 9 |
74 | 71 | 3 | 9 |
Test statistic under H0
Hence the test statistic value is 1.172.
c) The p-value is .137
Graph is not drawn to scale. The shaded region represents the area corresponding to the p-value of 0.137.
d) Since p-value is greater than significance level of 0.05, we fail to reject the null hypothesis.
Hence we conclude that at level, we fail to reject the null hypothesis and conclude that the data are not statistically significant.
e) Our conclusion in the context of the application is,
Fail to reject the null hypothesis, there is insufficient evidence to claim that the population score on the last round is higher than that on the first.