1. An object 1.50 cm high is held 2.80 cm from a person's cornea, and its...

1. An object 1.50 cm high is held 2.80 cm from a person's cornea, and its reflected image is measured to be 0.162 cm high.

(a)What is the magnification?

(b)Where is the image (in cm)? (cm (from the corneal "mirror"))

(c) Find the radius of curvature (in cm) of the convex mirror formed by the cornea. (Note that this technique is used by optometrists to measure the curvature of the cornea for contact lens fitting. The instrument used is called a keratometer, or curve measurer.)

2. The side mirrors on cars are convex mirrors. If the side mirror on the driver side of your car has a focal length with a magnitude of 2.20 m and a truck is at a distance of 4.00 m from the mirror, determine the following.

(a) image distance of the truck (Include the appropriate positive or negative sign.)
(b) magnification for this object distance (Include the appropriate positive or negative sign.)

Expert Solution

genius_generous answered 2 years ago

An object is placed 10.6 cm in front of the cornea. (The cornea is thin ans...

An object is placed 10.6 cm in front of the cornea. (The cornea is thin ans has approximately parallel sides so that the reflection that occurs as light travels from air to cornea to aqueous humor is essentially the same as though the aqueous humor were directly in contact with the air. The aqueous humor has index of refraction n = 1.34 and the radius of curvature of cornea is 7.8 mm.) a) What is the image distance for the...

An object 2.87 cm high is placed 19.9 cm from a convex mirror with a focal...

An object 2.87 cm high is placed 19.9 cm from a convex mirror with a focal length of 7.70 cm. (a) Find the position of the image. Your response differs from the correct answer by more than 100%. cm (b) Find the magnification of the mirror. (c) Find the height of the image. Your response differs from the correct answer by more than 100%. cm Suppose the object is moved so it is 3.85 cm from the same mirror. Repeat...

An object 2.00 cm high is placed 30.8 cm to the left of a converging lens...

An object 2.00 cm high is placed 30.8 cm to the left of a converging lens having a focal length of 25.8 cm. A diverging lens having a focal length of −20.0 cm is placed 110 cm to the right of the converging lens. (Use the correct sign conventions for the following answers.) (a) Determine the final position and magnification of the final image. (Give the final position as the image distance from the second lens.) final position :__________ cm...

A 1.00 cm-high object is placed 3.40 cm to the left of a converging lens of...

A 1.00 cm-high object is placed 3.40 cm to the left of a converging lens of focal length 8.95 cm. A diverging lens of focal length −16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm ---Select--- behind the...

A 2 cm high object is positioned 5 cm to the right of a converging lens...

A 2 cm high object is positioned 5 cm to the right of a converging lens (f= +3 cm). A diverging lens (f= -15 cm) is located 10 cm to the left of the converging lens. Determine its location and if the final image is inverted and virtual. Show ray tracing diagram to prove your answer.

A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal...

A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal length 9.00 cm. A diverging lens of focal length −16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image.

A 14 mm high object is 11 cm from a concave mirror with focal length 16...

A 14 mm high object is 11 cm from a concave mirror with focal length 16 cm. Calculate (a) the location of the image, (b) the height of the image, and (c) the type of image.

An object 5 centimeters high is placed 15 cm in front of a converging lens with...

An object 5 centimeters high is placed 15 cm in front of a converging lens with focal length 5 cm. Using graph paper (turn the paper so that the long side is horizontal) and a straight edge, draw appropriate rays to locate the image. Chose a scale (tell me what it is!) such that the lens is in the center of the page and the object is near the left side of the page a. Is the image real or...

(1) (A)Where does an object need to be placed relative to a microscope for its 0.250-cm...

(1) (A)Where does an object need to be placed relative to a microscope for its 0.250-cm focal length objective to produce a magnification of−100?(Give your answer to at least three decimal places.) Where should the 5.00-cm focal length eyepiece be placed to produce a further fourfold (4.00) magnification? (B)What magnification is produced by a 0.150 cm focal length microscope objective that is 0.155 cm from the object being viewed? What is the overall magnification if an eyepiece that produces a...

1a. Calculate the height of the image formed when a 2.1 cm high object is placed...

1a. Calculate the height of the image formed when a 2.1 cm high object is placed 17 cm away from a lens with focal length -10.5 cm. (Give your answer in cm) b. When 720 nm wavelength light is diffracted through a double slit the angle of the first dark fringe on each side of the center of the diffraction pattern is 3.5 degrees. Calculate the spacing between the double slits. (Give your answer in meters.) c. Two red bottles...

Question