Question

In: Physics

A 2 cm high object is positioned 5 cm to the right of a converging lens...

A 2 cm high object is positioned 5 cm to the right of a converging lens (f= +3 cm). A diverging lens (f= -15 cm) is located 10 cm to the left of the converging lens. Determine its location and if the final image is inverted and virtual. Show ray tracing diagram to prove your answer.

Solutions

Expert Solution


Related Solutions

An object 5 centimeters high is placed 15 cm in front of a converging lens with...
An object 5 centimeters high is placed 15 cm in front of a converging lens with focal length 5 cm. Using graph paper (turn the paper so that the long side is horizontal) and a straight edge, draw appropriate rays to locate the image. Chose a scale (tell me what it is!) such that the lens is in the center of the page and the object is near the left side of the page a. Is the image real or...
An object 2.00 cm high is placed 30.8 cm to the left of a converging lens...
An object 2.00 cm high is placed 30.8 cm to the left of a converging lens having a focal length of 25.8 cm. A diverging lens having a focal length of −20.0 cm is placed 110 cm to the right of the converging lens. (Use the correct sign conventions for the following answers.) (a) Determine the final position and magnification of the final image. (Give the final position as the image distance from the second lens.) final position :__________ cm...
A 1.00 cm-high object is placed 3.40 cm to the left of a converging lens of...
A 1.00 cm-high object is placed 3.40 cm to the left of a converging lens of focal length 8.95 cm. A diverging lens of focal length −16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm  ---Select--- behind the...
A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal...
A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal length 9.00 cm. A diverging lens of focal length −16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image.
A converging lens forms an image 20 centimeters  high of an object that is 5 centimeters high....
A converging lens forms an image 20 centimeters  high of an object that is 5 centimeters high. part a calculate the magnification factor m of the lens part b Explain how you can calculate the distance from the object if you know the lens has a focal length of  f centimeters. part c If the lens has a focal length of 10 centimeters calculate the distance to the image if the object is placed at a distance of 25 centimeters from the...
an object 3.0cm high object is place 4.0cm in front of a converging lens with a...
an object 3.0cm high object is place 4.0cm in front of a converging lens with a focal length of 8.0cm. the object is located on the principal axis. part 1. the image that will be formed will be . real, virtual or neither? part 2. the image will be loacted on the same side of the lens at a distance of __ from the lens? part 3. the magnification of the image will be ? part 4. the size of...
An object 20 cm tall is placed at 50 cm in front of a converging lens...
An object 20 cm tall is placed at 50 cm in front of a converging lens with a focal length of 5 cm. A. Find the location and nature of the image. B. Draw the diagram
A lens of focal length f1 = +20 cm has an object positioned 50 cm in...
A lens of focal length f1 = +20 cm has an object positioned 50 cm in front of it. A second lens of focal length f2= -15 cm is located 10 cm behind the first lens. a) Determine the two image positions for this combination of lenses. b) Is each image real or virtual, upright or inverted, and magnified or demagnified?
A converging lens has a focal length of 15 cm. If an object is placed at...
A converging lens has a focal length of 15 cm. If an object is placed at a distance of 5 cm from the lens, a. find the image position d i = _____ cm (include sign +/-) b. find the magnification M = _____(include sign +/-) c. characterize the resulting image. ________(real or virtual) ________(enlarged or reduced) ________(upright or inverted)
a) The focal length of a converging lens is 35 cm. An object is placed 100...
a) The focal length of a converging lens is 35 cm. An object is placed 100 cm in front of the lens. Describe the image. b) The focal length of a converging lens is 35 cm. An object is placed 30 cm in front of the lens. Describe the image. c) The focal length of a diverging lens is 35 cm. An object is placed 100 cm in front of the lens. Describe the image. d) The focal length of...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT