Question

In: Physics

C) One day on the lake we went between the dots. The following times were measured....

C) One day on the lake we went between the dots. The following times were measured. 240 seconds, 20 minutes, 10.6 minutes and 45 minutes. I started at 10am, what time did I pass the last dot? And how long did it take?

Uppgift 2

A) How many dl of sugar do I get if I collect everything in a jar. The small bowl has ¾ dl sugar and between the bowl has 3/8 dl sugar?

B) Then mix 1.5 dl of liquid. 12% was water, 48% was milk and 40% was cream. How many dl did I take from each part?

Uppgift 3

A) What speed do I keep if I cut a distance of 20km in 15 minutes?

B) To calculate the effect in a liquid cooler, I used the following method Effect = flow / h * energy content of the liquid * temperature difference.

20 l / min, 4.18kJ / kg * K, 10K. How big is it?

C) To calculate the resistance, I used the following method:

1 / R = 1 / R1 + 1 / R2 + 1 / R3. R1 = 4, R2 = 3, R3 = 4 What is the resistance R?

D) What will be the current I if U = I * R and U = 12Volt

E) Calculate the power P = U * I

Solutions

Expert Solution

C.

Here the total time to pass last dot is given as,

T = 4+20 +10.6 +45 min = 79.6 minutes = 1.32666hrs

So that time i passed last dot will be 10 + 1.3266 = 11.3266 am.

And it will take total 1.32666 hrs .

Uppgift 2

A. Total dl of sugar in the jar will be = 3/4 + 3/8 = 9/8 dl

B.Here ,

Total mix = 1.5 dl of liquid.

12% was water then its dl = 12×1.5/100= 0.18 dl

48% was milk so its dl = 48×1.5/100 = 0.72 dl

and 40% was cream so its dl = 40×1.5 /100 = 0.60 dl

Uppgift 3

A. Speed = 20 ×1000/ 15 ×60 = 22.222 m/s

B.Here the formula given as,

Effect = flow / h * energy content of the liquid * temperature difference

Flow = 20 l/ min = 1200 l per hour

4.18kJ / kg * K = 4180 J/kg K

Temperature= 10K.

On substitution of values we will get,

Effect = 50,160,000

C. Here given that,

1 / R = 1 / R1 + 1 / R2 + 1 / R3 = 0.8333 where,

R1 = 4, R2 = 3, R3 = 4

So that R = 1.2 ohm

D. I = U/R = 12/ 1.2 = 10 A

E. P = UI = 12 ×10 = 120 Watts.


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