In: Math
We flip a fair coin 20 times. Find the probability that we obtain between 8 and 17 heads, inclusively. Show work and please explain to someone that hardly understands statistics!
a coin has two side,head and tail
so,P(head), p = 0.5
1-p=1-0.5
1-p=0.5
here no. of times coin flip,n = 20
applying binomial probability,
here,P(X = x) = 20Cx * 0.5x * 0.520-x
P(8 < X < 17) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14 + P(X = 15) + P(X = 16) + P(X = 17)
= 20C8 * 0.58 * 0.512 + 20C9 * 0.59 * 0.511 + 20C10 * 0.510 * 0.510 + 20C11 * 0.511 * 0.59 + 20C12 * 0.512 * 0.58 + 20C13 * 0.513 * 0.57 + 20C14 * 0.514 * 0.56 + 20C15 * 0.515 * 0.55 + 20C16 * 0.516 * 0.54 + 20C17 * 0.517 * 0.53
= 0.8682