How would you prepare 250ml of 0.035M sodium sulfate solution? Describe steps starting from calculating amount...

How would you prepare 250ml of 0.035M sodium sulfate solution? Describe steps starting from calculating amount of sodium sulfate to final volume. What is the ionic strength of this solution (assuming the salt is ionized completely). (MW of Sodium sulfate (decahydrate) = 322.20)

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Expert Solution

Given : Volume of final solution = 250 mL = 0.250 L In this solution molarity of Sodium sulfate= 0.035

Solution :

Step 1) Calculation of mass of sodium sulfate from its molarity:

Mol sodium sulfate = Molarity * volume in L = 0.035 M * 0.250 L = 0.00875 mol

Mass of sodium sulfate = mol sodium sulfate * Molar mass of sodium sulfate

=0.00875 mol * 142.04 g/mol (molar mass of sodium sulfate = 142.04 g/mol )

= 1.243 g

Step 2 ) Measure accurately 1.243 g mass of sodium sulfate and take that in 250 mL volumetric flask.

Step 3) Fill the flask by distilled water near about half and stir slowly.

Step 4) after dissolving all the sodium sulfate in the water fill the flask up to the mark and the solution is ready with 0.035 M

Q2 Ionic strength : Sodium sulfate ( Na2SO4 )

This is calculated by following equation

I =

queen_honey_blossom answered 1 year ago

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