Describe and explain how one would prepare a 500ml of 0.525M solution from a 6M HNO3...

Describe and explain how one would prepare a 500ml of 0.525M solution from a 6M HNO3 stock solution.

Expert Solution

initial final

M1 = 6M M2 = 0.525M

V1 = V2 = 500ml

M1V1 = M2V2

V1 = M2V2/M1

= 0.525*500/6 = 43.75ml

volume of water = V2-V1

= 500-43.75 = 456.25ml

456.25ml of water added to 6M HNo3 to converted to 0.525M HNO3

queen_honey_blossom answered 1 year ago

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