___ FeCl3 (aq) + ___ NaOH (aq) -->
Fe(OH)3 (___) + ___ NaCl (___)
Balance the reaction, and enter phases for the products. You
do not need to submit this for this assignment, but it will help
you solve the problem.
A 0.532 M NaOH solution is added to 39.4 mL of a 0.398 M
FeCl3 solution. What is the volume of NaOH in mL that
must be added to completely react with the FeCl3
solution?
Reaction 1: NaOH(s)--> NaOH (aq)
Reaction 2: NaOH(s) + HCl (aq)--> NaCl(aq)+H2O(l)
Reaction 3: NaOH(aq) +HCl (aq) --> NaCl (aq) + H2O (L)
1) Describe each reaction as endothermic or exothermic and
explain your reasoning.
2) Examine the chemical equations for the three reactions.
Determine their relationship in a way that is consistent with
Hess's Law. (i.e. verify that Hess's Law is upheld. Reaction 3 is
the target equation).
3) Why is heat a stoichiometric quality?
4) Just what IS...
A solution of 0.2152M NaOH is used to neutralize 15.00mL H2SO4
solution.
H2SO4(aq) + 2NaOH(aq) ?
Na2SO4(aq) + 2H2O(l)
If 32.59mL NaOH solution is required to reach the endpoint, what
is the molarity of the H2SO4 solution?
Al(OH)3(s) + HCl(aq) --> AlCl3(aq) + H2O(I) a) balance the
equation b)calculate the number of grams s of HCl that can reacct
with 0.500 g of Al(OH)3. c) calculate the number of AlCl3 and the
number of grams of H2O formed when 0.500g of Al(OH)3 reacts. d)
show that your calculations from parts b and c are consistent with
the law of conservation of mass.
2 K[Al(OH)4](aq) + H2SO4(aq) ⟶ K2SO4(aq) + Al2O3(s) +
2H2O(l)
K2SO4(aq) + Al2O3(s) + 3 H2SO4(aq) ⟶ 2 KAl(SO4)2(aq) + 3
H2O(l).
What is the mole-to-mole ratio between the K[Al(OH)4](aq) and
the KAl(SO4)3(aq) product in this reaction?
What is the overall mole-to-mole ratio between the aluminum
metal reactant and the alum product, KAl(SO4)2•12 H2O(s)
HNO2 (aq) + NaOH (aq) → NaNO2 (aq) +
H2O
(l)
Ka of HNO2 = 4.5 x 10-4
H2O (l) + NO2- (aq) ↔
HNO2 (aq) + OH- (aq)
Kb of NO2- = 2.2 x
10-11
Exactly 100 mL of 0.10 M nitrous acid (HNO2) are
titrated with a 0.10 M NaOH solution. Calculate the pH for:
A:The initial solution
B:At the half-equivalence point
C:The point at which 80 mL of the base has been added
D:The equivalence point...
Given :
NaOH (aq) + HCl (aq) -> H2O (l) + NaCl (aq)
Mass of 1.00M HCl (diluted in water) : 60.925g
Vol of 1.00M HCl : 60.3mL
Mass of 1.00M NaOH : 50.500g
Vol of 1.00M NaOH : 50.0mL
---------------------------------------------------------------------------------------
1. Find mole of product if: (show calculations)
A. HCl is the limiting reactant: ______
B. NaOH is the limiting reactant: ______
2. FInd the actual limiting reactant: ______