___ FeCl3 (aq) + ___ NaOH (aq) -->
Fe(OH)3 (___) + ___ NaCl (___)
Balance the reaction, and enter phases for the products. You
do not need to submit this for this assignment, but it will help
you solve the problem.
A 0.532 M NaOH solution is added to 39.4 mL of a 0.398 M
FeCl3 solution. What is the volume of NaOH in mL that
must be added to completely react with the FeCl3
solution?
Reaction 1: NaOH(s)--> NaOH (aq)
Reaction 2: NaOH(s) + HCl (aq)--> NaCl(aq)+H2O(l)
Reaction 3: NaOH(aq) +HCl (aq) --> NaCl (aq) + H2O (L)
1) Describe each reaction as endothermic or exothermic and
explain your reasoning.
2) Examine the chemical equations for the three reactions.
Determine their relationship in a way that is consistent with
Hess's Law. (i.e. verify that Hess's Law is upheld. Reaction 3 is
the target equation).
3) Why is heat a stoichiometric quality?
4) Just what IS...
Consider the reaction: FeS(s) + 2HCl (aq) --> FeCl2(aq) +
2H2S(g). A 4.00g sample of FeS containing nonsulfuide impurities
reacted with HCl to give 896mL of H2S at 14C and 782 mmHg.Calculate
mass percent purity of the sample. State your final answer using 3
Sig figs
A solution of 0.2152M NaOH is used to neutralize 15.00mL H2SO4
solution.
H2SO4(aq) + 2NaOH(aq) ?
Na2SO4(aq) + 2H2O(l)
If 32.59mL NaOH solution is required to reach the endpoint, what
is the molarity of the H2SO4 solution?
Al(OH)3(s) + HCl(aq) --> AlCl3(aq) + H2O(I) a) balance the
equation b)calculate the number of grams s of HCl that can reacct
with 0.500 g of Al(OH)3. c) calculate the number of AlCl3 and the
number of grams of H2O formed when 0.500g of Al(OH)3 reacts. d)
show that your calculations from parts b and c are consistent with
the law of conservation of mass.
2 K[Al(OH)4](aq) + H2SO4(aq) ⟶ K2SO4(aq) + Al2O3(s) +
2H2O(l)
K2SO4(aq) + Al2O3(s) + 3 H2SO4(aq) ⟶ 2 KAl(SO4)2(aq) + 3
H2O(l).
What is the mole-to-mole ratio between the K[Al(OH)4](aq) and
the KAl(SO4)3(aq) product in this reaction?
What is the overall mole-to-mole ratio between the aluminum
metal reactant and the alum product, KAl(SO4)2•12 H2O(s)
HNO2 (aq) + NaOH (aq) → NaNO2 (aq) +
H2O
(l)
Ka of HNO2 = 4.5 x 10-4
H2O (l) + NO2- (aq) ↔
HNO2 (aq) + OH- (aq)
Kb of NO2- = 2.2 x
10-11
Exactly 100 mL of 0.10 M nitrous acid (HNO2) are
titrated with a 0.10 M NaOH solution. Calculate the pH for:
A:The initial solution
B:At the half-equivalence point
C:The point at which 80 mL of the base has been added
D:The equivalence point...