2 K[Al(OH)4](aq) + H2SO4(aq) ⟶ K2SO4(aq) + Al2O3(s) + 2H2O(l) K2SO4(aq) + Al2O3(s) + 3 H2SO4(aq)...

2 K[Al(OH)4](aq) + H2SO4(aq) ⟶ K2SO4(aq) + Al2O3(s) + 2H2O(l)

K2SO4(aq) + Al2O3(s) + 3 H2SO4(aq) ⟶ 2 KAl(SO4)2(aq) + 3 H2O(l).

What is the mole-to-mole ratio between the K[Al(OH)4](aq) and the KAl(SO4)3(aq) product in this reaction?

What is the overall mole-to-mole ratio between the aluminum metal reactant and the alum product, KAl(SO4)2•12 H2O(s)

Solutions

Expert Solution

2 K[Al(OH)4](aq) + H2SO4(aq) ⟶ K2SO4(aq) + Al2O3(s) + 2H2O(l)

2 moles 1 mole

K2SO4(aq) + Al2O3(s) + 3 H2SO4(aq) ⟶ 2 KAl(SO4)2(aq) + 3 H2O(l).

1 mole 2 moles

The mole-to-mole ratio between the K[Al(OH)4](aq) and the KAl(SO4)3(aq) 1:1 ratio >>>>>answer

2Al + 2KOH + 4H2So4 + 24H2O ----------------> 2KAlSO4.12 H2O + 3H2

The ratio of Al and 2KAlSO4.12 H2O is 1:1 >>>>answer

queen_honey_blossom answered 1 year ago

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