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A solution of 0.2152M NaOH is used to neutralize 15.00mL H2SO4 solution. H2SO4(aq) + 2NaOH(aq) ?...

A solution of 0.2152M NaOH is used to neutralize 15.00mL H2SO4 solution.

H2SO4(aq) + 2NaOH(aq) ? Na2SO4(aq) + 2H2O(l)

If 32.59mL NaOH solution is required to reach the endpoint, what is the molarity of the H2SO4 solution?

Solutions

Expert Solution

H2SO4(aq) + 2NaOH(aq) ? Na2SO4(aq) + 2H2O(l)

Acid                                      Base

M1   =                                      M2 =0.2152M

V1   =   15ml                           V2   =32.59 ml

n1   =   1                                    n1    =2

M1V1                                     M2V2

   n1                                                         n2

M1 = M2V2n1/n2V1

    = 0.2152*32.59*1/2*15 = 0.2337M

queen_honey_blossom answered 2 months ago
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