In: Statistics and Probability
The following data was collected to explore how the average number of hours a student studies per night and the student's GPA affect their ACT score. The dependent variable is the ACT score, the first independent variable (x1x1) is the number of hours spent studying, and the second independent variable (x2x2) is the student's GPA.
Study Hours | GPA | ACT Score |
---|---|---|
22 | 22 | 1717 |
33 | 22 | 1818 |
33 | 22 | 1818 |
55 | 22 | 2121 |
55 | 44 | 2727 |
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Step 1 of 2 :
Find the p-value for the regression equation that fits the given data. Round your answer to four decimal places.
What variables did you put in the x an y input cells?
We have to find the p-value for the regression equation that fits the given data.
We calculate the above p-value for the regression equation using Excel function "Data Analysis"
We put variables in the x an y input cells is as below
x1 = Study Hours
x2 = GPA
y = ACT Score
We write the above 3 variables y, x1 and x2 in Excel Spreadsheet is as below
y | x1 | x2 |
1717 | 22 | 22 |
1818 | 33 | 22 |
1818 | 33 | 22 |
2121 | 55 | 22 |
2727 | 55 | 44 |
Then using Regression command in Data Analysis and then select input y Range and input x Range as (x1,x2) variable at a time. then output of ANOVA becomes is as below.
ANOVA
F | Significance F | ||||
Regression | Regression | Regression | Regression | 633.6 | 0.001575796 |
Residual | Residual | Residual | Residual | ||
Total | 4 | 681426.8 |
Here,the p-value for the regression equation that fits the given data is in last column that is Significance F
p-value = 0.001575796 0.0016 (Round answer up to four decimal places)
p-value = 0.0016
The p-value for the regression equation that fits the given data is 0.0016
Summary :-
The p-value for the regression equation that fits the given data is 0.0016
We put variables in the x an y input cells is
x1 = Study Hours
x2 = GPA
y = ACT Score