In: Statistics and Probability
Create a random data set consisting of two different samples, drawn from Census data that contains numeric values - such as age. Show details of the sourcing.
State the null and alternate hypothesis in words that apply to the topic you are addressing. Perform a two-sided, two-sample t-test. Explain what you are doing.
Show the graph of the test will all features shown and labeled
State the conclusion of the test and grounds.
The graphs are:


| No prescription | Prescription | |
| count | 11 | 11 | 
| mean | 35.7200 | 33.0127 | 
| sample standard deviation | 2.6415 | 3.6660 | 
| sample variance | 6.9777 | 13.4394 | 
| minimum | 29.98 | 28.12 | 
| maximum | 38.75 | 39.51 | 
| range | 8.77 | 11.39 | 
| 1st quartile | 34.8650 | 30.2950 | 
| median | 36.7800 | 31.4500 | 
| 3rd quartile | 37.2100 | 35.9450 | 
| interquartile range | 2.3450 | 5.6500 | 
| mode | 37.2100 | #N/A | 
| low extremes | 0 | 0 | 
| low outliers | 1 | 0 | 
| high outliers | 0 | 0 | 
| high extremes | 0 | 0 | 
The independent samples t-test assuming equal variance will be used here.
The hypothesis being tested is:
H0: µ1 = µ2
H1: µ1 ≠ µ2
| No prescription | Prescription | |
| 35.7200 | 33.0127 | mean | 
| 2.6415 | 3.6660 | std. dev. | 
| 11 | 11 | n | 
| 20 | df | |
| 2.70727 | difference (No prescription - Prescription) | |
| 10.20857 | pooled variance | |
| 3.19509 | pooled std. dev. | |
| 1.36239 | standard error of difference | |
| 0 | hypothesized difference | |
| 1.987 | t | |
| .0608 | p-value (two-tailed) | 
The p-value is 0.0608.
Since the p-value (0.0608) is greater than the significance level (0.05), we fail to reject the null hypothesis.
Therefore, we can conclude that µ1 = µ2.
| No prescription | Prescription | 
| 34.5 | 35.75 | 
| 37.21 | 29.75 | 
| 32.25 | 37.23 | 
| 38.24 | 36.14 | 
| 38.75 | 33.54 | 
| 35.23 | 31.27 | 
| 35.65 | 28.12 | 
| 37.21 | 30.84 | 
| 36.78 | 31.45 | 
| 37.12 | 29.54 | 
| 29.98 | 39.51 |