In: Chemistry
Using the following data reactions:
| ?H |
Given H2(g) + Cl2(g)
2HCl(g) :
H0 =
-184KJ
--------------- (1)
H2(g)
2H(g) :
H01
=
432KJ
----------------(2)
Cl2(g)
2Cl(g) :
H02
= 239
KJ
---------------- (3)
The formation of HCl can be expressed as
H-H + Cl-Cl
2 H-Cl
Thus the reaction indicates that,
(1) One Cl-Cl bond is broken
(2) One H-H bond is broken
(3) Two H-Cl bonds are formed
The enthalpy change for the reaction will be given by
H0 = (
H0Cl-Cl
+
H0H-H)
- ( 2x
H0H-Cl
)
( 2x
H0H-Cl
) = (
H0Cl-Cl
+
H0H-H)
-
H0
= ( 239 KJ + 432KJ ) - (-184KJ )
= 855 KJ
H0H-Cl
= 855 / 2
= 427.5 KJ
Therefore energy of an H-Cl bond is 427.5 KJ