A dioxin-contaminated water source contains 0.082% dioxin by mass. How much dioxin is present in 2.6...

A dioxin-contaminated water source contains 0.082% dioxin by mass.

How much dioxin is present in 2.6 L of this water? Assume a density of 1.00 g/mL.

Express your answer using two significant figures.

m=_____g

Expert Solution

Ans. Given-

[Dioxin] = 0.082 % (w/w) = 0.082 g dioxin / 100 g solution

Vol. of water or solution = 2.6 L = 2600.0 mL

Density of solution = 1.00 g mL^-1

# Mass of water or solution = Vol. x Density = 2600.0 g x 1.00 g mL^-1 = 2600.0 g

# Now,

Amount of dioxin = [Dioxin] x Mass of water

= (0.082 g dioxin / 100 g water) x 2600.0 g water

= 2.132 g = 2.1 g

queen_honey_blossom answered 2 years ago

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