an expanding gas absorbs 1.55 kj of heat. if its internal energy increases by 1.32 kj....

an expanding gas absorbs 1.55 kj of heat. if its internal energy increases by 1.32 kj. A) what quantity of work is involved? B) Estimate the change in H for the process.

Expert Solution

Given the absorbed heat , q = +1.55 kJ ( the +ve sign indicates that heat is absorbing by the system)

The increase in internal energy , dU = 1.32 kJ

According to first law of thermodynamics , q = dU + W

Where W = work done = ?

Plug the values we get W = q - dU

= +1.55 - 1.32 kJ

= 0.23 kJ

Therefore the quantity of work involved is 0.23 kJ

The enthalpy change involved is , dH = dU+pdV

= dU + W

Therefore dH = q = +1.55 kJ

queen_honey_blossom answered 2 hours ago

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