Question

In: Statistics and Probability

The following table contains information of 11 years of quaterly sales for KYRYH product Year Q1...

The following table contains information of 11 years of quaterly sales for KYRYH product

Year

Q1

Q2

Q3

Q4

Total

2006

37000

31000

27500

33800

129300

2007

38500

31700

27000

35000

132200

2008

40000

33000

28400

36000

137400

2009

41320

33000

29300

35800

139420

2010

42600

35200

30300

38400

146500

2011

42000

33000

28500

39000

142500

2012

43000

37800

32300

40600

153700

2013

47000

37000

31200

40000

155200

2014

46000

39000

28000

40500

153500

2015

49000

42300

33500

44000

168800

2016

52700

44000

33600

45700

176000

a) Determine the demand using mobile average

b) Comment on the validity of the model based on the confidence level of 95%

Solutions

Expert Solution

ARIMA

Call:
arima(x = t1$State, order = c(0, 0, 1))

Coefficients:
ma1 intercept
1.0000 532317.887
s.e. 0.0862 8065.284

sigma^2 estimated as 796544702: log likelihood = -561.95, aic = 1129.91

Training set error measures:
ME RMSE MAE MPE MAPE MASE ACF1
Training set 434.6242 28223.12 24476.33 -0.4190657 4.569171 4.436563 0.8137388

Exponential smoothing

Forecast method: Simple exponential smoothing

Model Information:
Simple exponential smoothing

Call:
ses(y = t1$State, h = 4, alpha = 0.2)

Smoothing parameters:
alpha = 0.2

Initial states:
l = 473812.6462

sigma: 20094.36

AIC AICc BIC
1138.961 1139.228 1142.704

Error measures:
ME RMSE MAE MPE MAPE MASE ACF1
Training set 14706.09 19671.27 17171.55 2.601553 3.122986 3.112504 0.8402502

Linear Regression

Call:

tslm(formula = State ~ trend, data = ts1)

Residuals:

Min 1Q Median 3Q Max

-34310 -7266 5109 13597 20552

Coefficients:

Estimate Std. Error t value Pr(>|t|)   

(Intercept) 442000.0 4761.4 92.83 <2e-16 ***

trend 3659.0 169.2 21.63 <2e-16 ***

---

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 16240 on 46 degrees of freedom

Multiple R-squared: 0.9105, Adjusted R-squared: 0.9085

F-statistic: 467.8 on 1 and 46 DF, p-value: < 2.2e-16

MAPE:  0.02580109

MSE: 252657325

Linear trend has the least MAPE so I would use that. Also, from the graph it is clear that linear trend gives the best result. The values of MAPE and MSE are all mentioned in the model results above.


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