C2H2 (g) + 3H2 (g) --> 2CH4 (g) ΔHf: 227 &n

C₂H₂ (g) + 3H₂ (g) --> 2CH₄ (g)

ΔH_f: 227 -75 (kJ/mol)

S°: 201 131 186 (J/mol K)

For the above reaction, what is ΔS, in J/mol K?

Expert Solution

Given:

S° of C2H2 = 201

S° of 3H2 = 131

S° of 2CH4 = 186

We will be calculating value of change in entropy of the reaction (ΔS).

ΔS = S_Products – S_Reactants

= 186 – (131 + 201)

ΔS = -146 J/mol K

queen_honey_blossom answered 2 years ago

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