In: Chemistry
1)
delts Sf (CH4) = 182.26 J/Kmol
delts Sf (C2H6) = 229.60 J/Kmol
delts Sf (H2) = 130.68 J/mol K
delta S(rxn) = delta S (H2) + delta S (C2H6) - 2* delta
S (CH4)
= 130.68 + 229.60 - 2*182.26
= -4.24 J/K mol
ANSWER: -4.24 J/K mol
2)
delts Sf (NH3) = 192.45 J/K mol
delts Sf (N2H4) = 121.21 J/K mol
delts Sf(H2) = 130.68 J/mol K
delta S(rxn) = delta S (H2) + delta S (N2H4) - 2* delta
S (NH3)
= 130.68 + 121.21 - 2*192.45
= -133.01 J/K mol
Answer: -133.01 J/K mol
3)
for sponataneous, delta G should be negative
delta G = delta H - T* delta S
If delta H (+) and delta S (-) then delta G will be come
positive
Hence it is not spontaneous